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72 lines
2.1 KiB
72 lines
2.1 KiB
library ieee; |
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use ieee.std_logic_1164.all; |
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use ieee.numeric_std.all; |
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use ieee.math_real.all; |
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entity plrufn is |
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generic ( |
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BITS : positive := 2 |
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) |
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; |
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port ( |
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acc : in std_ulogic_vector(BITS-1 downto 0); |
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tree_in : in std_ulogic_vector(2 ** BITS - 2 downto 0); |
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tree_out : out std_ulogic_vector(2 ** BITS - 2 downto 0); |
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lru : out std_ulogic_vector(BITS-1 downto 0) |
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); |
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end entity plrufn; |
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architecture rtl of plrufn is |
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-- Each level of the tree (from leaf to root) has half the number of nodes |
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-- of the previous level. So for a 2^N bits LRU, we have a level of N/2 bits |
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-- one of N/4 bits etc.. down to 1. This gives us 2^N-1 nodes. Ie, 2 bits |
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-- LRU has 3 nodes (2 + 1), 4 bits LRU has 15 nodes (8 + 4 + 2 + 1) etc... |
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constant count : positive := 2 ** BITS - 1; |
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subtype node_t is integer range 0 to count - 1; |
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begin |
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get_lru: process(tree_in) |
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variable node : node_t; |
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variable abit : std_ulogic; |
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begin |
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node := 0; |
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for i in 0 to BITS-1 loop |
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abit := tree_in(node); |
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if is_X(abit) then |
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abit := '0'; |
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end if; |
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lru(BITS-1-i) <= abit; |
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if i /= BITS-1 then |
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node := node * 2; |
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if abit = '1' then |
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node := node + 2; |
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else |
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node := node + 1; |
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end if; |
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end if; |
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end loop; |
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end process; |
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update_lru: process(all) |
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variable node : node_t; |
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variable abit : std_ulogic; |
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begin |
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tree_out <= tree_in; |
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node := 0; |
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for i in 0 to BITS-1 loop |
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abit := acc(BITS-1-i); |
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if is_X(abit) then |
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abit := '0'; |
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end if; |
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tree_out(node) <= not abit; |
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if i /= BITS-1 then |
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node := node * 2; |
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if abit = '1' then |
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node := node + 2; |
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else |
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node := node + 1; |
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end if; |
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end if; |
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end loop; |
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end process; |
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end;
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